User talk:Neil Parker

Discussion on Pythagorean triples

In the interests of possible further improvements on the page, may I humbly suggest that some careful thought be given to the slight contradiction posed by my contribution: namely that on the one hand the Platonic sequence is said to be a 'special case' of the general formula (m^2-n^2,2mn,m^2+n^2) with n=1 whilst on the other it can be shown that the 'general formula' itself may be derived from the Platonic sequence ([t^2-1]/2;t;[t^2+1]/2) when the parameter t is a rational number m/n.

That's not a contradiction – one of the triplets is just 2n^2 times the other. BTW, I'm a little puzzled by this article. Is there some particular point you want to illustrate? The pictures are nice, but the article needs some sort of a wrapper around it, or something. It lacks focus as it stands. DavidCBryant 16:32, 28 August 2007 (UTC)[reply]

Duplicate images uploaded

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You don't need to sign articles you write, just things on talk pages and so forth. Cheers. Zelse81 07:14, 23 August 2007 (UTC)[reply]

Re: Diophantus II.VIII

1. Thanks for your message. Re the adding/subtracting, the Latin runs "Communis adiiciatur utrimque defectus, & à similibus auferantur similia". A translation close to the original could read "I add the negative terms found on both sides, and similarly subtract the common [positive] term". The paraphrase by Bashmakova which I used spells out for the reader what the subtracted positive term (16) and the added negative terms (x^2+16x) are. This has the advantage of making the mathematics clearer for the modern reader but the disadvantage, as you point out, of moving further away from the Latin text. If you think the disadvantage outweighs the advantage, I have no objection to using a closer translation.
2. The problem with the use of Diophantine triple is that Diophantine triple is used to mean something else, viz., a triple of rational numbers such that the product of any two is one less than a square (cf. e.g. [1]. The reference here, in the numbering used by Heath (1885), is to Arithmetica IV.20.) Since ${\displaystyle (1;{\frac {2t}{t^{2}+1}};{\frac {t^{2}-1}{t^{2}+1}})}$ will generate integral triples after clearing denominators, I believe the statement currently in the article is correct, with this clarification.
3. For the role of t, in modern language, what is going on is that a Pythagorean triple is equivalent to a rational point on the unit circle, which, over the rational numbers, is birationally equivalent to the line. So, under a suitable birational equivalence (implictly found by Diophantus), any rational point on the circle gives a rational point on the line, which is t. Spacepotato (talk) 22:22, 26 November 2007 (UTC)[reply]

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Ptolemy's theorem

Please go back and fix your major new section to conform to normal heading case, and include citation of your sources. Dicklyon (talk) 19:39, 26 March 2008 (UTC)[reply]

Thanks for working on Ptolemy's theorem. It's still not clear to me how the reference relates to what you wrote. There's nothing in Hawking about sines, or not much anyway that I can find. It would be useful to have a footnote near the first intro of the interpretation from cut-the-knot, and a footnote for at least the first corrolary from Hawking, from Copernicus, etc. Let me know if you need help making footnotes; just explain to me what's from where. Dicklyon (talk) 05:01, 28 March 2008 (UTC)[reply]

Ptolemy's Part 2

re: http://en.wikipedia.org/wiki/Ptolemy%27s_theorem, my talk comment, I refer to this one: [2]. If I have the quadrilateral dimensions ie all blue dimensions, I presume the circle is fixed, and I'd like to see the formula for it. thanks--Billymac00 (talk) 03:45, 1 July 2008 (UTC)[reply]

Query on mortgages - response

I've responded on my talk page...--Gregalton (talk) 03:46, 24 April 2009 (UTC)[reply]

Re: Orphan

The best way to de-orphan an article is to add a link to it from a realted page - for example, for your article, there may be an opportunity on Compound Interest to link. This helps relate the article to other concepts already in Wikipedia. You could also try searching for similar terms (make sure if you use the article's title as a search term, you press "search" instead of "go" in the search bar). Finally, there are some suggestions here on other methods to try. Hope that helps. Nikkimaria (talk) 11:37, 1 May 2009 (UTC)[reply]

Talkback

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File copyright problem with File:RC-circuit-step-response.png

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Cleanup tag

From Wikipedia:Cleanup:

• Continuous_Repayment_Mortgage. As an author of this article I find it extremely irritating to find an anonymous 'cleanup' tag suddenly pasted in at the top. If this is going to happen, then surely it is only etiquette for the editor/moderator to identify himself/herself or at least post a clarification on the article's talk page. Could someone please indicate whether Wikipedia policy approves the posting of anonymous cleanup tags and - if not - where I should direct a formal complaint. Thanks. Neil Parker (talk) 10:44, 12 June 2010 (UTC)[reply]

The instructions on Template:Cleanup does advise editors applying the tag to explain the specific problems with the article on the talk page. This isn't a "policy", but is useful etiquette advice. However, many editors - including myself - apply the tag without any explanation on the talk page when they believe the problems with the article are obvious. I think the best guidance is Wikipedia:Assume good faith; in this situation, instead of filing a complaint seeking punishment, the most productive thing to do is to ask the editor who placed the tag what problems they see in the article. While you are awaiting their reply, it's fine to say on the talk page something like "I don't see any problems with the article, so I'm removing the cleanup tag. Feel free to re-add it if you have specific complaints you can list on the talk page." Cleanup tag additions are never anonymous; you can always find the editor who added it by looking under the "View history" tab from the article page. -- Beland (talk) 15:50, 20 July 2010 (UTC)[reply]

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Continuous-repayment mortgage

Thanks for your message; I have replied at length on Talk:Continuous-repayment mortgage. -- Beland (talk) 04:05, 28 June 2013 (UTC)[reply]

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Interesting approach to teaching mathematics

Perhaps you have seen this ("Better Explained")? - K (talk) 16:17, 23 March 2018 (UTC)[reply]

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