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Laceyville, Pennsylvania
Laceyville is a borough that is located in Wyoming County, Pennsylvania, United States. The population was 363 at the time of the 2020 census.[3] GeographyLaceyville is located at 41°38′43″N 76°9′38″W / 41.64528°N 76.16056°W (41.645337, -76.160451).[4] According to the United States Census Bureau, the borough has a total area of 0.2 square miles (0.52 km2), all land. Demographics
At the 2000 census,[8] there were 379 people, 160 households and 102 families residing in the borough. The population density was 1,895 inhabitants per square mile (732/km2). There were 185 housing units at an average density of 925 per square mile (357/km2). The racial makeup of the borough was 94.5% White, 0.5% African American, 4.7% some other race, and 0.3% from two or more races. Hispanic or Latino of any race were 7.9% of the population. There were 160 households, of which 32.5% had children under the age of eighteen living with them; 44.4% were married couples living together, 13.1% had a female householder with no husband present, and 36.3% were non-families. 32.5% of all households were made up of individuals, and 12.5% had someone living alone who was sixty-five years of age or older. The average household size was 2.37 and the average family size was 2.89. 23.7% of the population were under the age of eighteen, 61.8% were aged eighteen to sixty-four, and 14.5% were aged sixty-five or older. The median age was 39.4 years. The median household income was $46,667 and the median family income was $58,542. Males had a median income of $32,125 compared with that of $25,000 for females. The per capita income was $18,594. Approximately 14.4% of families and 15.1% of the population were living below the poverty line, including 22.6% of those who were under the age of eighteen and 18.2% of those who were aged sixty-five or older. Gallery
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