1928 tennis event results
First-seeded Helen Wills defeated Eileen Bennett 6–1, 6–2 in the final to win the women's singles tennis title at the 1928 French Championships.[1] The draw consisted of 37 players of which 8 were seeded.
Seeds
The seeded players are listed below. Helen Wills is the champion; others show the round in which they were eliminated.
Helen Wills (champion)
Suzanne Devé (second round)
Kea Bouman (semifinals)
Daphne Akhurst (quarterfinals)
Elisabeth Macready (second round)
Lilly De Alvarez (first round)
Marguerite Bordes (third round)
Eileen Bennett (finalist)
Draw
Key
Finals
Earlier rounds
Section 1
Section 2
Section 3
Section 4
References
- ^ Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York]: New Chapter Press. p. 393. ISBN 978-0942257700.
External links