After encountering some users who opt to reply on their own talk pages (and for some very good reasons), I have come to a conclusion: a compromise. If you initiate a discussion on my talk page, I will reply on my talk page, but, I will notify you on your talk page via a short statement (ex. ==RE: Subject== See reply on my talk page) and will do this every time a post a reply. This way, not only are conversations not fragmented, but you will know if I've acknowledged your comment. This will not be done if the conversation will probably only consist of a question and a reply. Promote good etiquette on talk pages! (Archives:2004, 2005, 2008)
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My name is Jonathan Obar user:Jaobar, I'm a professor in the College of Communication Arts and Sciences at Michigan State University and a Teaching Fellow with the Wikimedia Foundation's Education Program. This semester I've been running a little experiment at MSU, a class where we teach students about becoming Wikipedia administrators. Not a lot is known about your community, and our students (who are fascinated by wiki-culture by the way!) want to learn how you do what you do, and why you do it. A while back I proposed this idea (the class) to the communityHERE, where it was met mainly with positive feedback. Anyhow, I'd like my students to speak with a few administrators to get a sense of admin experiences, training, motivations, likes, dislikes, etc. We were wondering if you'd be interested in speaking with one of our students.
So a few things about the interviews:
Interviews will last between 15 and 30 minutes.
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I saw the wiki page, but I couldn't find any examples using actual numbers evaluating the formula. Could you give some examples of convolution, please? Mathijs Krijzer (talk) 22:14, 9 March 2013 (UTC)[reply]
Definition
The convolution of f and g is written f∗g, using an asterisk or star. It is defined as the integral of the product of the two functions after one is reversed and shifted. As such, it is a particular kind of integral transform:
The convolution of two complex-valued functions on Rd
is well-defined only if f and g decay sufficiently rapidly at infinity in order for the integral to exist. Conditions for the existence of the convolution may be tricky, since a blow-up in g at infinity can be easily offset by sufficiently rapid decay in f. The question of existence thus may involve different conditions on f and g.
Circular discrete convolution
When a function gN is periodic, with period N, then for functions, f, such that f∗gN exists, the convolution is also periodic and identical to:
When multiplying two polynomials, the coefficients of the product are given by the convolution of the original coefficient sequences, extended with zeros where necessary to avoid undefined terms; this is known as the Cauchy product of the coefficients of the two polynomials.
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An RfC that you may be interested in...
As one of the previous contributors to {{Infobox film}} or as one of the commenters on it's talk page, I would like to inform you that there has been a RfC started on the talk page as to implementation of previously deprecated parameters. Your comments and thoughts on the matter would be welcomed. Happy editing!
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Following a community discussion in June 2011, consensus was reached to provisionally suspend the administrative permissions of users who have been inactive for one year (i.e. administrators who have not made any edits or logged actions in over one year). As a result of this discussion, your administrative permissions will be removed pending your return if you do not return to activity within the next several days. If you wish to have these permissions reinstated should this occur, please post to the Wikipedia:Bureaucrats' noticeboard and the userright will be restored per the re-sysopping process (i.e. as long as the attending bureaucrats are reasonably satisfied that your account has not been compromised, that your inactivity did not have the effect of evading scrutiny of any actions which might have led to sanctions, and that you have not been inactive for a three year period of time). If you remain inactive for a three year period of time, including the present year you have been inactive, you will need to request reinstatement at WP:RFA. This removal of access is procedural only, and not intended to reflect negatively upon you in any way. We wish you the best in future endeavors, and thank you for your past administrative efforts. MadmanBot (talk) 00:51, 27 March 2014 (UTC)[reply]
Suspension of administrative permissions due to inactivity
Following a community discussion in June 2011, consensus was reached to provisionally suspend the administrative permissions of users who have been inactive for one year (i.e. administrators who have not made any edits or logged actions in over one year). As a result of this discussion, your administrative permissions have been removed pending your return. If you wish to have these permissions reinstated, please post to the Wikipedia:Bureaucrats' noticeboard and the userright will be restored per the re-sysopping process (i.e. as long as the attending bureaucrats are reasonably satisfied that your account has not been compromised, that your inactivity did not have the effect of evading scrutiny of any actions which might have led to sanctions, and that you have not been inactive for a three year period of time). If you remain inactive for a three year period of time, including the present year you have been inactive, you will need to request reinstatement at WP:RFA. This removal of access is procedural only, and not intended to reflect negatively upon you in any way. We wish you the best in future endeavors, and thank you for your past administrative efforts. –xenotalk17:30, 7 April 2014 (UTC)[reply]
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Hello, Edward Z. Yang. Voting in the 2016 Arbitration Committee elections is open from Monday, 00:00, 21 November through Sunday, 23:59, 4 December to all unblocked users who have registered an account before Wednesday, 00:00, 28 October 2016 and have made at least 150 mainspace edits before Sunday, 00:00, 1 November 2016.
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Hello, Edward Z. Yang. Voting in the 2016 Arbitration Committee elections is open from Monday, 00:00, 21 November through Sunday, 23:59, 4 December to all unblocked users who have registered an account before Wednesday, 00:00, 28 October 2016 and have made at least 150 mainspace edits before Sunday, 00:00, 1 November 2016.
The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail.
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![{\displaystyle (f*g_{N})[n]\equiv \sum _{m=0}^{N-1}\left(\sum _{k=-\infty }^{\infty }{f}[m+kN]\right)g_{N}[n-m].\,}](https://wikimedia.org/api/rest_v1/media/math/render/svg/85512f0cc63fbdc3ecff2a1565b830297ec71bb7)
![{\displaystyle (f*g_{T})(t)\equiv \int _{t_{0}}^{t_{0}+T}\left[\sum _{k=-\infty }^{\infty }f(\tau +kT)\right]g_{T}(t-\tau )\,d\tau ,}](https://wikimedia.org/api/rest_v1/media/math/render/svg/46ca67ae76bc1e6841511aa12fab10aed9cb970d)
![{\displaystyle (f*g)[n]\ {\stackrel {\mathrm {def} }{=}}\ \sum _{m=-\infty }^{\infty }f[m]\,g[n-m]}](https://wikimedia.org/api/rest_v1/media/math/render/svg/271b9c48087f01b626627a423d8e9003aa765728)
![{\displaystyle =\sum _{m=-\infty }^{\infty }f[n-m]\,g[m].}](https://wikimedia.org/api/rest_v1/media/math/render/svg/f067498b1393be11cf4cecfb08f3096f14bdce59)
