Nothing in the assumptions mentions the continuum: the hypotheses are purely algebraic. It therefore seems quite magical that [the division ring over which the Hilbert space is defined] is forced to be the real numbers, complex numbers or quaternions.[6]
Writing a decade after Solèr's original publication, Pitowsky calls her theorem "celebrated".[7]
Statement
Let be a division ring. That means it is a ring in which one can add, subtract, multiply, and divide but in which the multiplication need not be commutative. Suppose this ring has a conjugation, i.e. an operation for which
Consider a vector space V with scalars in , and a mapping
which is -linear in left (or in the right) entry, satisfying the identity
This is called a Hermitian form. Suppose this form is non-degenerate in the sense that
For any subspace S let be the orthogonal complement of S. Call the subspace "closed" if
Call this whole vector space, and the Hermitian form, "orthomodular" if for every closed subspace S we have that is the entire space. (The term "orthomodular" derives from the study of quantum logic. In quantum logic, the distributive law is taken to fail due to the uncertainty principle, and it is replaced with the "modular law," or in the case of infinite-dimensional Hilbert spaces, the "orthomodular law."[6])
A set of vectors is called "orthonormal" if The result is this:
If this space has an infinite orthonormal set, then the division ring of scalars is either the field of real numbers, the field of complex numbers, or the ring of quaternions.