Meduza Island

Meduza Island
Meduza Island is located in Antarctica
Meduza Island
Meduza Island
Location of Meduza Island
Meduza Island is located in Antarctic Peninsula
Meduza Island
Meduza Island
Meduza Island (Antarctic Peninsula)
Geography
LocationAntarctica
Coordinates65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W / -65.02556; -64.08472
ArchipelagoWilhelm Archipelago
Area11.9 ha (29 acres)
Length670 m (2200 ft)
Width434 m (1424 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Populationuninhabited

Meduza Island (Bulgarian: остров Медуза, romanized: ostrov Meduza, IPA: [ˈɔstrof mɛˈduzɐ]) is the partly ice-covered island extending 670 m in southwest–northeast direction and 434 m in north–south direction in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 11.9 ha.[1]

The feature is so named because of its shape supposedly resembling a jellyfish ('meduza' in Bulgarian), and in association with other descriptive names of islands in the area.[1]

Location

Meduza Island is located at 65°01′32″S 64°05′05″W / 65.02556°S 64.08472°W / -65.02556; -64.08472, which is 3.18 km southwest of Kosatka Island, 509 m west-northwest of Greblo Island, 2.33 km northwest of Rollet Island, 1.26 km east-northeast of Yastreb Island and 1.4 km southeast of Tyulen Island. British mapping in 2001.

Maps

See also

Notes

  1. ^ a b Meduza Island. SCAR Composite Gazetteer of Antarctica

References

This article includes information from the Antarctic Place-names Commission of Bulgaria which is used with permission.