The constant (euler number) in the inequality is optimal, that is, the inequality does not always hold if is replaced by a smaller number. The inequality is strict (it holds with "<" instead of "≤") if some element in the sequence is non-zero.
Integral version
Carleman's inequality has an integral version, which states that
where MG stands for geometric mean, and MA — for arithmetic mean. The Stirling-type inequality applied to implies
for all
Therefore,
whence
proving the inequality. Moreover, the inequality of arithmetic and geometric means of non-negative numbers is known to be an equality if and only if all the numbers coincide, that is, in the present case, if and only if for . As a consequence, Carleman's inequality is never an equality for a convergent series, unless all vanish, just because the harmonic series is divergent.
By Hardy’s inequality
One can also prove Carleman's inequality by starting with Hardy's inequality[5]: §334
for the non-negative numbers , ,… and , replacing each with , and letting .
Versions for specific sequences
Christian Axler and Mehdi Hassani investigated Carleman's inequality for the specific cases of where is the th prime number. They also investigated the case where .[6] They found that if one can replace with in Carleman's inequality, but that if then remained the best possible constant.
Notes
^T. Carleman, Sur les fonctions quasi-analytiques, Conférences faites au cinquième congres des mathématiciens Scandinaves, Helsinki (1923), 181-196.
^Duncan, John; McGregor, Colin M. (2003). "Carleman's inequality". Amer. Math. Monthly. 110 (5): 424–431. doi:10.2307/3647829. MR2040885.
Hardy, G. H.; Littlewood J.E.; Pólya, G. (1952). Inequalities, 2nd ed. Cambridge University Press. ISBN0-521-35880-9.
Rassias, Thermistocles M., ed. (2000). Survey on classical inequalities. Kluwer Academic. ISBN0-7923-6483-X.
Hörmander, Lars (1990). The analysis of linear partial differential operators I: distribution theory and Fourier analysis, 2nd ed. Springer. ISBN3-540-52343-X.