2017–18 Vijay Hazare Trophy
The 2017–18 Vijay Hazare Trophy was the 25th edition of the Vijay Hazare Trophy, an annual List A cricket tournament in India. It was held between 5 and 27 February 2018.[1] Tamil Nadu were the defending champions.[2] In December 2017, the fixtures were brought forward to allow players to practice ahead of the 2018 Indian Premier League.[3][4] Following the conclusion of the group stages, Baroda and Karnataka from Group A, Maharashtra and Delhi from Group B, Andhra and Mumbai from Group C, and Hyderabad and Saurashtra from Group D had progressed to the knockout stage of the competition.[5][6][7][8] On the first day of quarter-final matches, Karnataka beat Hyderabad by 103 runs and Maharashtra beat Mumbai by 7 wickets to advance to the semi-finals.[9][10] In the other two quarter-finals, Saurashtra beat Baroda by 3 wickets and Andhra beat Delhi by 6 wickets to progress.[11][12] It was the first time that Andhra had reached the semi-finals of the Vijay Hazare Trophy.[13] In the first semi-final, Karnataka beat Maharashtra by 9 wickets to advance to the final.[14] In the second semi-final, Saurashtra beat Andhra by 59 runs to progress.[15] In the final, Karnataka beat Saurashtra by 41 runs to win the tournament.[16] Karnataka's Mayank Agarwal scored 723 runs during the tournament and scored 2,141 runs across all formats, the highest total by any batsman in an Indian domestic season.[17] TeamsThe teams were drawn in the following groups:
Group APoints table
Source: [18]
Group BPoints table
Source: [18]
Group CPoints table
Source: [18]
Group DPoints table
Source: [18]
Knockout stage
Quarter-finals
Semi-finals
Final
References
External links |