2005 Heineken Open – Singles 2005 tennis event results
Fernando González defeated Olivier Rochus 6–4, 6–2 to win the 2005 Heineken Open singles competition. Dominik Hrbatý was the defending singles champion of the tennis tournament, held in Auckland, New Zealand.[1]
Seeds
A champion seed is indicated in bold text while text in italics indicates the round in which that seed was eliminated.
Draw
Key
References
External links
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Grand Slam events | |
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ATP Masters Series | |
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ATP International Series Gold | |
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ATP International Series |
- Adelaide (S, D)
- Doha (S, D)
- Chennai (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Viña del Mar (S, D)
- Delray Beach (S, D)
- Milan (S, D)
- Marseille (S, D)
- San Jose (S, D)
- Buenos Aires (S, D)
- Bahia (S, D)
- Scottsdale (S, D)
- Valencia (S, D)
- Casablanca (S, D)
- Houston (S, D)
- Estoril (S, D)
- Munich (S, D)
- St. Pölten (S, D)
- Düsseldorf
- Halle (S, D)
- London/Queen's Club (S, D)
- 's-Hertogenbosch (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Indianapolis (S, D)
- Amersfoort (S, D)
- Umag (S, D)
- Los Angeles (S, D)
- Sopot (S, D)
- Washington (S, D)
- New Haven (S, D)
- Beijing (S, D)
- Bucharest (S, D)
- Palermo (S, D)
- Ho Chi Minh City (S, D)
- Bangkok (S, D)
- Metz (S, D)
- Stockholm (S, D)
- Basel (S, D)
- Lyon (S, D)
- St. Petersburg (S, D)
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Team events | |
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