1999 Great American Insurance ATP Championships – Doubles 1999 tennis event results
Mark Knowles and Daniel Nestor were the defending champions, but lost in semifinals to Todd Woodbridge and Mark Woodforde.
Jonas Björkman and Byron Black won the title, by defeating Woodbridge and Woodforde 6–3, 7–6(8–6) in the final.[1][2]
Seeds
The first four seeds received a bye into the second round.
Draw
Key
Finals
Top half
Bottom half
Qualifying
Qualifying seeds
Qualifiers
Qualifying draw
First qualifier
Second qualifier
References
External links
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Grand Slam events | |
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Mercedes Super 9 | |
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ATP Championship Series |
- Memphis (S, D)
- Rotterdam (S, D)
- London (S, D)
- Barcelona (S, D)
- Tokyo (S, D)
- Stuttgart (S, D)
- Kitzbühel (S, D)
- Indianapolis (S, D)
- Washington (S, D)
- Singapore (S, D)
- Vienna (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Marseille (S, D)
- St. Petersburg (S, D)
- Dubai (S, D)
- San Jose (S, D)
- Scottsdale (S, D)
- Copenhagen (S, D)
- Casablanca (S, D)
- Hong Kong (S, D)
- Estoril (S, D)
- Chennai (S, D)
- Orlando (S, D)
- Prague (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Delray Beach (S, D)
- St. Pölten (S, D)
- Halle (S, D)
- Merano (S, D)
- London (S, D)
- 's-Hertogenbosch (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Los Angeles (S, D)
- Umag (S, D)
- Amsterdam (S, D)
- San Marino (S, D)
- Boston (S, D)
- Long Island (S, D)
- Majorca (S, D)
- Bournemouth (S, D)
- Tashkent (S, D)
- Toulouse (S, D)
- Bucharest (S, D)
- Shanghai (S, D)
- Basel (S, D)
- Palermo (S, D)
- Lyon (S, D)
- Stockholm (S, D)
- Moscow (S, D)
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Team events | |
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