1998 NAIA World Series

1998 NAIA
baseball tournament

1998 NAIA World Series
Teams	8
Format	Double elimination Page playoff
Finals site	Drillers Stadium Tulsa, Oklahoma
Champions	Albertson (1st title)
Winning coach	Tim Mooney
MVP	Chris Bradshaw (OF) (Oklahoma City)

The 1998 NAIA World Series was the 42nd annual tournament hosted by the National Association of Intercollegiate Athletics to determine the national champion of baseball among its member colleges and universities in the United States and Canada.[1]

The tournament was played, for the one and only time, at Drillers Stadium in Tulsa, Oklahoma.

Albertson (55–8) defeated Indiana Tech (46–22) in a single-game championship series, 6–3, to win the Coyotes' first NAIA World Series.

Oklahoma City outfielder Chris Bradshaw was named tournament MVP. Bradshaw would be the last player until 2023 to win tournament MVP on a non-championship winning team.

Bracket

	First round				Upper Second Round				Upper Third Round				Semifinals				Third place final				Championship final
	Cumberland (TN)	8
	Point Park	4
					Cumberland	4
					Indiana Tech	16
	Indiana Tech	11
	St. Thomas (FL)	2
									Indiana Tech	5
									Albertson	19
	Albertson	8
													Albertson	4
	Culver–Stockton	7
					Albertson	6							Oklahoma City	5
					Bellevue	4
	Bellevue (NE)	7
	Oklahoma City	2																			Albertson	6
																	Oklahoma City	6			Indiana Tech	3
					Lower Second Round				Lower Third Round								Indiana Tech	8
									Cumberland	3
					Culver–Stockton	6			Oklahoma City	18
													Indiana Tech	7
					Oklahoma City	9
													Bellevue	4
									Bellevue	16
					Point Park	8			St. Thomas	8
					St. Thomas	13^(10)

See also

• 1998 NCAA Division I baseball tournament
• 1998 NCAA Division II baseball tournament
• 1998 NCAA Division III baseball tournament
• 1998 NAIA Softball World Series

References

1. "Championship History" (PDF). NAIA.org. National Association of Intercollegiate Athletics. Retrieved September 14, 2022.