1998 Chevrolet Cup – Doubles 1998 tennis event results
Hendrik Jan Davids and Andrew Kratzmann were the defending champions, but did not participate this year.
Mariano Hood and Sebastián Prieto won the title, defeating Massimo Bertolini and Devin Bowen 7–6, 6–7, 7–6 in the final.
Seeds
Draw
Key
Draw
References
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Grand Slam events | |
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Mercedes Super 9 | |
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ATP Championship Series |
- Antwerp (S, D)
- Memphis (S, D)
- Philadelphia (S, D)
- London (S, D)
- Barcelona (S, D)
- Tokyo (S, D)
- Stuttgart (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Singapore (S, D)
- Vienna (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Marseille (S, D)
- Split (S, D)
- Dubai (S, D)
- St. Petersburg (S, D)
- San Jose (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Copenhagen (S, D)
- Casablanca (S, D)
- Hong Kong (S, D)
- Estoril (S, D)
- Chennai (S, D)
- Orlando (S, D)
- Prague (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Coral Springs (S, D)
- St. Pölten (S, D)
- Halle (S, D)
- London/Queen's Club (S, D)
- Bologna (S, D)
- 's-Hertogenbosch (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Los Angeles (S, D)
- Umag (S, D)
- Kitzbühel (S, D)
- Amsterdam (S, D)
- San Marino (S, D)
- Long Island (S, D)
- Boston (S, D)
- Bournemouth (S, D)
- Tashkent (S, D)
- Bucharest (S, D)
- Toulouse (S, D)
- Majorca (S, D)
- Basel (S, D)
- Palermo (S, D)
- Shanghai (S, D)
- Ostrava (S, D)
- Lyon (S, D)
- Mexico City (S, D)
- Bogotá (S, D)
- Santiago (S, D)
- Moscow (S, D)
- Stockholm (S, D)
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Team events | |
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