1996 Romanian Open – Doubles 1996 tennis event results
Mark Keil and Jeff Tarango were the defending champions but only Tarango competed that year with David Ekerot.
Ekerot and Tarango won in the final 7–6, 7–6 against David Adams and Menno Oosting.[1]
Seeds
Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.
- Libor Pimek / Byron Talbot (semifinals)
- David Adams / Menno Oosting (final)
- n/a
- David Ekerot / Jeff Tarango (champions)
Draw
Key
References
External links
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Grand Slam events | |
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Mercedes Super 9 | |
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ATP Championship Series |
- Antwerp (S, D)
- Memphis (S, D)
- Milan (S, D)
- Philadelphia (S, D)
- Barcelona (S, D)
- Tokyo (S, D)
- Stuttgart Outdoor (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Vienna (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Auckland (S, D)
- Jakarta (S, D)
- Sydney (S, D)
- Shanghai (S, D)
- Zagreb (S, D)
- Dubai (S, D)
- Marseille (S, D)
- San Jose (S, D)
- Mexico City (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Copenhagen (S, D)
- St. Petersburg (S, D)
- Casablanca (S, D)
- Estoril (S, D)
- Hong Kong (S, D)
- New Delhi (S, D)
- Bermuda (S, D)
- Seoul (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Prague (S, D)
- Pinehurst (S, D)
- Coral Springs (S, D)
- St. Pölten (S, D)
- London/Queen's Club (S, D)
- Oporto (S, D)
- Rosmalen (S, D)
- Bologna (S, D)
- Halle (S, D)
- Nottingham (S, D)
- Båstad (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Kitzbühel (S, D)
- Amsterdam (S, D)
- Los Angeles (S, D)
- San Marino (S, D)
- Umag (S, D)
- Long Island (S, D)
- Bogotá (S, D)
- Bournemouth (S, D)
- Bucharest (S, D)
- Basel (S, D)
- Palermo (S, D)
- Lyon (S, D)
- Marbella (S, D)
- Singapore (S, D)
- Beijing (S, D)
- Ostrava (S, D)
- Tel Aviv (S, D)
- Toulouse (S, D)
- Moscow (S, D)
- Santiago (S, D)
- Stockholm (S, D)
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Team events | |
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