1948 U.S. National Championships – Women's singles
Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the women's singles tennis title at the 1948 U.S. National Championships.[1][2] SeedsThe seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]
DrawKey
Final eight
References
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